In standards you will often see that wind pressure on a pole, conductor etc is reduced by cos² (or sin² depending on the orientation of angles) of the angle between wind direction and object direction but there is no explanation of why cos is squared. Here is the explanation.

When moving air (wind) is stopped by a surface the dynamic energy in the wind is transformed to pressure.^{1} The pressure on the surface transforms to a force.^{2}

where

\(q\) = dynamic pressure

\(\rho\) = air density

\(v\) = wind velocity

where

\(F\) = force on the surface

\(A\) = surface area

Air density \(\rho\) may be taken as 1.225 kg/m³ ^{3} which leads to equation B4 in AS7000:2016

with \( V\) in equation 3 being the same as \( v\) in equation 1.

When the wind is not perpendicular to the surface its velocity is reduced by cos of the angle between the wind and the perpendicular^{4}, ie in equation 1 \(v\) becomes \(v \cdot cos \varphi\).

Substituting eqn 1 into eqn 2 means eqn 2 becomes

\(\large F=q \times cos^{2} \varphi \times A \tag{4}\)showing that wind pressure \(q\) (Pa in metric units) is reduced by the square of cos of the angle between wind and perpendicular to the surface.

- Derivation at https://www.grc.nasa.gov/www/k-12/airplane/dynpress.html
- https://www.engineeringtoolbox.com/wind-load-d_1775.html
- https://www.skybrary.aero/index.php/International_Standard_Atmosphere_(ISA)
- Miao, Ren, Minshan, Jiang Zhang, Xigang, Zhu, Gregor Holzner, Dan Liu and Changpeng. “Study on longitudinal wind load calculation method of cables for cable-stayed bridge.” (2009).